# Reconstruct Original Digits from English



Given a non-empty string containing an out-of-order English representation of digits 0-9, output the digits in ascending order.

#### Example

**Example 1:**

```
Input: "owoztneoer"

Output: "012"
```

**Example 2:**

```
Input: "fviefuro"

Output: "45"
```

#### Notice

* Input contains only lowercase English letters.
* Input is guaranteed to be valid and can be transformed to its original digits. That means invalid inputs such as "abc" or "zerone" are not permitted.
* Input length is less than 50,000.

分析

找出s中每个数字的特有的char, nums\[num] = s.count(char）

```
class Solution:
    """
    @param s: a string
    @return: return a string
    """
    def originalDigits(self, s):
        # write  your code here
        nums = [0 for x in range(10)]
        nums[0] = s.count('z')
        nums[2] = s.count('w')
        nums[4] = s.count('u')
        nums[6] = s.count('x')
        nums[8] = s.count('g')
       
        nums[3] = s.count('h') - nums[8]
        nums[7] = s.count('s') - nums[6]
        nums[5] = s.count('v') - nums[7]
        nums[1] = s.count('o') - nums[0] - nums[2] - nums[4]
        nums[9] = (s.count('n') - nums[1] - nums[7]) // 2
        res = ''
        for i in range(10):
            res += str(i) * nums[i]
        return res
        

```
