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# 1539. Kth Missing Positive Number

number

Given an array `arr` of positive integers sorted in a **strictly increasing order**, and an integer `k`.

Return *the* `k`<sup>`th`</sup> ***positive** integer that is **missing** from this array.*

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**Example 1:**

<pre><code><strong>Input: arr = [2,3,4,7,11], k = 5
</strong><strong>Output: 9
</strong><strong>Explanation: The missing positive integers are [1,5,6,8,9,10,12,13,...]. The 5th missing positive integer is 9.
</strong></code></pre>

**Example 2:**

<pre><code><strong>Input: arr = [1,2,3,4], k = 2
</strong><strong>Output: 6
</strong><strong>Explanation: The missing positive integers are [5,6,7,...]. The 2nd missing positive integer is 6.
</strong></code></pre>

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**Constraints:**

* `1 <= arr.length <= 1000`
* `1 <= arr[i] <= 1000`
* `1 <= k <= 1000`
* `arr[i] < arr[j]` for `1 <= i < j <= arr.length`

分析

直接遍历数组，一边计算当前缺失了几个数字，一边找。

```
class Solution:
    def findKthPositive(self, arr: List[int], k: int) -> int:
        missing = 0
        current = 1
        i = 0
        while True:
            if i < len(arr) and arr[i] == current:
                i += 1
            else:
                missing += 1
                if missing == k:
                    return current
            current += 1

```
