Longest Increasing Path in a Matrix

Given an integer matrix, find the length of the longest increasing path.

From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed).

Example 1:

Input: nums = 
[
  [9,9,4],
  [6,6,8],
  [2,1,1]
] 
Output: 4 
Explanation: The longest increasing path is [1, 2, 6, 9].

Example 2:

Input: nums = 
[
  [3,4,5],
  [3,2,6],
  [2,2,1]
] 
Output: 4 
Explanation: The longest increasing path is [3, 4, 5, 6]. Moving diagonally is not allowed.

分析

memorize 用dp数组记录已经算过的,dp这里也起了visited的作用

几个边界条件

1visited dfs开始就用DP返回

2 x,y过界和没有递增,在for loop里continue掉

DFS

BFS

每次while找出不可达点(出度为0),每一次while loop就是一层,层里是当前Level里所有的不可达点,加入visited。

就是先找出终点,然后变成可达。一直到最后到达最后一个起点,就是最长的路径。注意这里只能找最长,耗尽到起点就是最长,无法找最短。(第一个到起点)

全部遍历完,多少level层数就是最长的Path。

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