> For the complete documentation index, see [llms.txt](https://nataliekung.gitbook.io/ladder_code/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://nataliekung.gitbook.io/ladder_code/qiang-hua-4-shuang-zhi-zhen-ff09/backspace-string-compare.md).

# Backspace String Compare

Given two strings `S` and`T`, return if they are equal when both are typed into empty text editors.`#`means a backspace character.

**Example 1:**

```
Input: 
S = 
"ab#c"
, T = 
"ad#c"
Output: 
true

Explanation
: Both S and T become "ac".
```

**Example 2:**

```
Input: 
S = 
"ab##"
, T = 
"c#d#"
Output: 
true

Explanation
: Both S and T become "".
```

**Example 3:**

```
Input: 
S = 
"a##c"
, T = 
"#a#c"
Output: 
true

Explanation
: Both S and T become "c".
```

**Example 4:**

```
Input: 
S = 
"a#c"
, T = 
"b"
Output: 
false

Explanation
: S becomes "c" while T becomes "b".
```

Note:

```
1 <= S.length <= 200
1 <= T.length <= 200
S and T only contain lowercase letters and '#' characters.
```

分析

栈内只加字母，不加#，遇到‘#’，抵消栈内char，字母的话加入。 最后比较S,T剩下的东西

```
class Solution:
    def backspaceCompare(self, S: str, T: str) -> bool:
        return self.getChar(S) == self.getChar(T)

    def getChar(self, S: str) -> str:
        stack = []
        for i in S:
            if stack and i == '#':
                stack.pop()
            elif i.isalpha():
                stack.append(i)
        return ''.join(stack)
```


---

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