Longest Continuous Increasing Subsequence(dp)
Input:
[1,3,5,4,7]
Output:
3
Explanation:
The longest continuous increasing subsequence is [1,3,5], its length is 3.
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input:
[2,2,2,2,2]
Output:
1
Explanation:
The longest continuous increasing subsequence is [2], its length is 1.
Note:Length of the array will not exceed 10,000.
分析
dp[]或者直接dp,dp[i] = nums[i-1]<nums[i]? dp[i-1] + 1: 1
注意python : if not nums
class Solution:
def findLengthOfLCIS(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
if not nums:
return 0
n = len(nums)
dp = maxp = 1
for i in range(1, n):
dp = dp+1 if nums[i] > nums[i-1] else 1
maxp = max(maxp,dp)
return maxp
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