# Longest Continuous Increasing Subsequence(dp)

```
Input:
```

```
 [1,3,5,4,7]

Output:
 3

Explanation:
 The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
```

**Example 2:**

```
Input:
 [2,2,2,2,2]

Output:
 1

Explanation:
 The longest continuous increasing subsequence is [2], its length is 1.
```

**Note:**Length of the array will not exceed 10,000.

分析

dp\[]或者直接dp，dp\[i] = nums\[i-1]\<nums\[i]? dp\[i-1] + 1: 1

注意python : if not nums

```
class Solution:
    def findLengthOfLCIS(self, nums):
        """
        :type nums: List[int]
        :rtype: int

        """
        if not nums:
            return 0
        n = len(nums)

        dp = maxp = 1
        for i in range(1, n):
            dp = dp+1 if nums[i] > nums[i-1] else 1
            maxp = max(maxp,dp)

        return maxp
```