Encode and Decode TinyURL
Note: This is a companion problem to the System Design problem: Design TinyURL.
TinyURL is a URL shortening service where you enter a URL such as https://leetcode.com/problems/design-tinyurl
and it returns a short URL such as http://tinyurl.com/4e9iAk
.
Design the encode
and decode
methods for the TinyURL service. There is no restriction on how your encode/decode algorithm should work. You just need to ensure that a URL can be encoded to a tiny URL and the tiny URL can be decoded to the original URL.
分析
可以直接用urls的len,urls存所有longurl。可以decode回去,直接得到index取出longurl
用某个数字mod62,然后取[A-Z, a-z, 0-9]间值。 这个数字可以用global counter或者len(urls).不能decode,只能把所有decoded short->long map存起来,decode直接取
别忘了存2个map,对重复longurl不用encode again
class Codec:
def __init__(self):
self.global_counter = 0
self.s2l = {}
self.l2s = {}
self.base = 'http://tinyurl.com/'
self.strs = string.ascii_letters+string.digits
def encode(self, longUrl):
"""Encodes a URL to a shortened URL.
:type longUrl: str
:rtype: str
"""
if longUrl not in self.l2s:
encoded = ''.join(random.choice(self.strs) for i in range(6))
self.s2l[encoded] = longUrl
self.l2s[longUrl] = encoded
self.global_counter += 1
return self.base + encoded
else:
return self.base+self.l2s[longUrl]
def decode(self, shortUrl):
"""Decodes a shortened URL to its original URL.
:type shortUrl: str
:rtype: str
"""
decoded = shortUrl[-6:]#shortUrl.split('/')[-1]
return self.s2l[decoded]
# def __init__(self):
# self.urls = []
# def encode(self, longUrl):
# self.urls.append(longUrl)
# return 'http://tinyurl.com/' + str(len(self.urls) - 1)
# def decode(self, shortUrl):
# return self.urls[int(shortUrl.split('/')[-1])]
# Your Codec object will be instantiated and called as such:
# codec = Codec()
# codec.decode(codec.encode(url))
Last updated
Was this helpful?