Maximal Square(matrix)

Given a 2D binary matrix filled with 0's and 1's, find the largest square containing only 1's and return its area.

Example:

Input: 

1 0 1 0 0
1 0 1 1 1
1 1 1 1 1
1 0 0 1 0

Output: 4

分析

res[i][j] = min(res[i - 1][j - 1], res[i - 1][j], res[i][j - 1]) + 1

因为矩阵要i-1,j-1 所以在dp外边框直接加一圈行列都设为0

class Solution:
    def maximalSquare(self, matrix):
        """
        :type matrix: List[List[str]]
        :rtype: int
        """
        if not matrix or not len(matrix):
            return 0
        n = len(matrix)
        m = len(matrix[0])

        res = [[0] * (m+1) for _ in range(n+1)]
        ans = 0
        for i in range(1,n+1):
            for j in range(1,m+1):
                if int(matrix[i-1][j-1]) == 1:                    
                    res[i][j] = min(res[i - 1][j - 1], res[i - 1][j], res[i][j - 1]) + 1
                ans = max(ans,res[i][j]*res[i][j])
        return ans